ln(x^2)-ln(2*x)+1=0

Solution for ln(x^2)-ln(2*x)+1=0 equation:

Simplifying
ln(x2) + -1ln(2x) + 1 = 0

Multiply ln * x2
lnx2 + -1ln(2x) + 1 = 0

Remove parenthesis around (2x)
lnx2 + -1ln * 2x + 1 = 0

Reorder the terms for easier multiplication:
lnx2 + -1 * 2ln * x + 1 = 0

Multiply -1 * 2
lnx2 + -2ln * x + 1 = 0

Multiply ln * x
lnx2 + -2lnx + 1 = 0

Reorder the terms:
1 + -2lnx + lnx2 = 0

Solving
1 + -2lnx + lnx2 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2lnx + -1 + lnx2 = 0 + -1

Reorder the terms:
1 + -1 + -2lnx + lnx2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2lnx + lnx2 = 0 + -1
-2lnx + lnx2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2lnx + lnx2 = -1

Reorder the terms:
1 + -2lnx + lnx2 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -2lnx + lnx2 = 0

The solution to this equation could not be determined.